Assertion (A): If sin2 A + sin A = 1 then cos4 A + cos2 A = 1.
Reason (R): 1 - sin2 A = cos2 A
Both A and R are true, and R is the correct explanation of A.
Both A and R are true, but R is not the correct explanation of A.
A is true, but R is false.
A is false, but R is true.
Answer
Given,
⇒ sin2 A + sin A = 1
⇒ sin A = 1 - sin2 A
⇒ sin A = cos2 A
Squaring both the sides, we get :
⇒ (sin A)2 = (cos2 A)2
⇒ sin2 A = cos4 A ......................(1)
Solving L.H.S. of cos4 A + cos2 A = 1, we get :
⇒ cos4 A + cos2 A
⇒ sin2 A + cos2 A [From equation (1)]
⇒ 1.
Since, L.H.S. = R.H.S.
∴ Assertion (A) is true.
As we know that, sin2 A + cos2 A = 1
⇒ 1 - sin2 A = cos2 A
∴ Reason (R) is true.
∴ Both (A) and (R) are true, and (R) is the correct explanation for (A).
Hence, option 1 is the correct option.
Assertion (A):
Reason (R): tan2 θ + sec2 θ = 1
Both A and R are true, and R is the correct explanation of A.
Both A and R are true, but R is not the correct explanation of A.
A is true, but R is false.
A is false, but R is true.
Answer
∴ Assertion (A) is true.
tan2 θ + sec2 θ = 1 is incorrect; the correct identity is sec2 θ − tan2 θ = 1.
∴ Reason (R) is false.
Hence, option 3 is the correct option.
Assertion (A): (1 − cosec2 θ)(1 − sec2 θ) = 1
Reason (R): 1 + tan2 θ = sec2 θ and 1 + cot2 θ = cosec2 θ
Both A and R are true, and R is the correct explanation of A.
Both A and R are true, but R is not the correct explanation of A.
A is true, but R is false.
A is false, but R is true.
Answer
Solving L.H.S,
(1 − cosec2 θ)(1 − sec2 θ)
= (− cot2 θ)(− tan2 θ) [∵ 1 − cosec2 θ = − cot2 θ and 1 − sec2 θ = − tan2 θ]
= (tan2 θ) = 1
∴ Assertion (A) is true.
1 + tan2 θ = sec2 θ and 1 + cot2 θ = cosec2 θ are standard identities, and these are exactly the relations used to simplify the Assertion.
∴ Reason (R) is true and is the correct explanation of A.
Hence, option 1 is the correct option.
Assertion (A): If sec θ + tan θ = p, then sec θ =
Reason (R): sec2 θ − tan2 θ = 1
Both A and R are true, and R is the correct explanation of A.
Both A and R are true, but R is not the correct explanation of A.
A is true, but R is false.
A is false, but R is true.
Answer
Given, sec θ + tan θ = p.
We know that sec2 θ − tan2 θ = 1.
⇒ (sec θ + tan θ)(sec θ − tan θ) = 1
⇒ (p)(sec θ − tan θ) = 1
⇒ sec θ − tan θ =
Adding sec θ + tan θ = p and sec θ − tan θ = :
⇒ 2 sec θ = p + =
⇒ sec θ = .
So the correct value is , not .
∴ Assertion (A) is false.
sec2 θ − tan2 θ = 1 is a standard Pythagorean identity.
∴ Reason (R) is true.
Hence, option 4 is the correct option.
Assertion (A): For an acute angle θ, if sin θ = cos θ, then 2 sin2 θ + tan2 θ = 2
Reason (R): For any acute angle θ, sin (90° − θ) = cos θ
Both A and R are true, and R is the correct explanation of A.
Both A and R are true, but R is not the correct explanation of A.
A is true, but R is false.
A is false, but R is true.
Answer
Given, sin θ = cos θ.
⇒ = 1 ⇒ tan θ = 1, which for an acute angle gives θ = 45°.
Also, sin θ = cos θ ⇒ sin2 θ = cos2 θ, and since sin2 θ + cos2 θ = 1, we get 2 sin2 θ = 1.
⇒ 2 sin2 θ + tan2 θ = 1 + (1)2 = 1 + 1 = 2.
∴ Assertion (A) is true.
sin (90° − θ) = cos θ is a true complementary-angle identity.
∴ Reason (R) is true.
However, the value 2 sin2 θ + tan2 θ = 2 is obtained using tan θ = 1 and 2 sin2 θ = 1, not from the complementary-angle relation. So R does not explain A.
Hence, option 2 is the correct option.
Assertion (A): If sec θ + tan θ = a and sec θ − tan θ = b then ab = 1.
Reason (R): sec2 θ - tan2 θ = 1
Both A and R are true, and R is the correct explanation of A.
Both A and R are true, but R is not the correct explanation of A.
A is true, but R is false.
A is false, but R is true.
Answer
Given,
⇒ sec θ + tan θ = a
⇒ sec θ − tan θ = b
⇒ ab = (sec θ + tan θ)(sec θ - tan θ)
⇒ ab = sec2 θ - tan2 θ
⇒ ab = 1
So assertion (A) is true.
We know that,
⇒ sec2 θ - tan2 θ = 1
This is a fundamental trigonometric identity.
So reason (R) is true.
Thus, Both (A) and (R) are true and (R) is the correct explanation of (A).
Hence, option 1 is the correct option.