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Chapter 22

Trigonometrical Identities — Assertion-Reason Type Questions

Class - 10 RS Aggarwal Mathematics Solutions



Assertion-Reason Type Questions

Question 1

Assertion (A): If sin2 A + sin A = 1 then cos4 A + cos2 A = 1.

Reason (R): 1 - sin2 A = cos2 A

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

Given,

⇒ sin2 A + sin A = 1

⇒ sin A = 1 - sin2 A

⇒ sin A = cos2 A

Squaring both the sides, we get :

⇒ (sin A)2 = (cos2 A)2

⇒ sin2 A = cos4 A ......................(1)

Solving L.H.S. of cos4 A + cos2 A = 1, we get :

⇒ cos4 A + cos2 A

⇒ sin2 A + cos2 A [From equation (1)]

⇒ 1.

Since, L.H.S. = R.H.S.

∴ Assertion (A) is true.

As we know that, sin2 A + cos2 A = 1

⇒ 1 - sin2 A = cos2 A

∴ Reason (R) is true.

∴ Both (A) and (R) are true, and (R) is the correct explanation for (A).

Hence, option 1 is the correct option.

Question 2

Assertion (A): (1+tanθ1+cotθ)2=tan2θ\Big(\dfrac{1 + \tan \theta}{1 + \cot \theta} \Big)^2 = \tan^2 \theta

Reason (R): tan2 θ + sec2 θ = 1

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

(1+tanθ1+cotθ)2(1+tanθ1+1tanθ)2(1+tanθtanθ+1tanθ)2tan2θ\Rightarrow \Big(\dfrac{1 + \tan \theta}{1 + \cot \theta} \Big)^2 \\[1em] \Rightarrow \Big(\dfrac{1 + \tan \theta}{1 + \dfrac{1}{\tan \theta}} \Big)^2 \\[1em] \Rightarrow \Big(\dfrac{1 + \tan \theta}{ \dfrac{\tan \theta + 1}{\tan \theta}} \Big)^2 \\[1em] \Rightarrow \tan^2 \theta

∴ Assertion (A) is true.

tan2 θ + sec2 θ = 1 is incorrect; the correct identity is sec2 θ − tan2 θ = 1.

∴ Reason (R) is false.

Hence, option 3 is the correct option.

Question 3

Assertion (A): (1 − cosec2 θ)(1 − sec2 θ) = 1

Reason (R): 1 + tan2 θ = sec2 θ and 1 + cot2 θ = cosec2 θ

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

Solving L.H.S,

(1 − cosec2 θ)(1 − sec2 θ)

= (− cot2 θ)(− tan2 θ) [∵ 1 − cosec2 θ = − cot2 θ and 1 − sec2 θ = − tan2 θ]

= 1tan2θ\dfrac{1}{\tan^2 \theta} (tan2 θ) = 1

∴ Assertion (A) is true.

1 + tan2 θ = sec2 θ and 1 + cot2 θ = cosec2 θ are standard identities, and these are exactly the relations used to simplify the Assertion.

∴ Reason (R) is true and is the correct explanation of A.

Hence, option 1 is the correct option.

Question 4

Assertion (A): If sec θ + tan θ = p, then sec θ = 2pp2+1\dfrac{2p}{p^2 + 1}

Reason (R): sec2 θ − tan2 θ = 1

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

Given, sec θ + tan θ = p.

We know that sec2 θ − tan2 θ = 1.

⇒ (sec θ + tan θ)(sec θ − tan θ) = 1

⇒ (p)(sec θ − tan θ) = 1

⇒ sec θ − tan θ = 1p\dfrac{1}{p}

Adding sec θ + tan θ = p and sec θ − tan θ = 1p\dfrac{1}{p} :

⇒ 2 sec θ = p + 1p\dfrac{1}{p} = p2+1p\dfrac{p^2 + 1}{p}

⇒ sec θ = p2+12p\dfrac{p^2 + 1}{2p}.

So the correct value is p2+12p\dfrac{p^2 + 1}{2p}, not 2pp2+1\dfrac{2p}{p^2 + 1}.

∴ Assertion (A) is false.

sec2 θ − tan2 θ = 1 is a standard Pythagorean identity.

∴ Reason (R) is true.

Hence, option 4 is the correct option.

Question 5

Assertion (A): For an acute angle θ, if sin θ = cos θ, then 2 sin2 θ + tan2 θ = 2

Reason (R): For any acute angle θ, sin (90° − θ) = cos θ

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

Given, sin θ = cos θ.

sinθcosθ\dfrac{\sin \theta}{\cos \theta} = 1 ⇒ tan θ = 1, which for an acute angle gives θ = 45°.

Also, sin θ = cos θ ⇒ sin2 θ = cos2 θ, and since sin2 θ + cos2 θ = 1, we get 2 sin2 θ = 1.

⇒ 2 sin2 θ + tan2 θ = 1 + (1)2 = 1 + 1 = 2.

∴ Assertion (A) is true.

sin (90° − θ) = cos θ is a true complementary-angle identity.

∴ Reason (R) is true.

However, the value 2 sin2 θ + tan2 θ = 2 is obtained using tan θ = 1 and 2 sin2 θ = 1, not from the complementary-angle relation. So R does not explain A.

Hence, option 2 is the correct option.

Question 6

Assertion (A): If sec θ + tan θ = a and sec θ − tan θ = b then ab = 1.

Reason (R): sec2 θ - tan2 θ = 1

  1. Both A and R are true, and R is the correct explanation of A.

  2. Both A and R are true, but R is not the correct explanation of A.

  3. A is true, but R is false.

  4. A is false, but R is true.

Answer

Given,

⇒ sec θ + tan θ = a

⇒ sec θ − tan θ = b

⇒ ab = (sec θ + tan θ)(sec θ - tan θ)

⇒ ab = sec2 θ - tan2 θ

⇒ ab = 1

So assertion (A) is true.

We know that,

⇒ sec2 θ - tan2 θ = 1

This is a fundamental trigonometric identity.

So reason (R) is true.

Thus, Both (A) and (R) are true and (R) is the correct explanation of (A).

Hence, option 1 is the correct option.

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