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Chapter 4

Factorisation — Assertion-Reason Type Questions

Class - 9 RS Aggarwal Mathematics Solutions



Assertion Reason Questions

Question 1

Assertion(A): One of the factors of (5x + 1)2 + (25x2 - 1) is 2x.

Reason(R): (a + b)2 = (a + b)(a + b) and a2 - b2 = (a + b)(a - b)

  1. A is true, R is false

  2. A is false, R is true

  3. Both A and R are true

  4. Both A and R are false

Answer

Given,

⇒ (5x + 1)2 + (25x2 - 1)

⇒ (5x + 1)2 + (5x)2 - (1)2

⇒ (5x + 1)2 + (5x + 1)(5x - 1)

⇒ (5x + 1)[(5x + 1) + (5x - 1)]

⇒ (5x + 1)(10x)

⇒ 2x(5)(5x + 1).

Assertion (A) is true.

⇒ (a + b)2 can be written as (a + b)(a + b)

By identity,

a2 - b2 = (a + b)(a - b)

Reason (R) is true.

Thus, both A and R are true.

Hence, option 3 is correct option.

Question 2

Assertion(A): a322b3a^3 - 2\sqrt{2}b^3 can be factorized as (a22)(a2+2ab+2b2)(a - 2\sqrt{2})(a^2 + \sqrt{2}ab + 2b^2)

Reason(R): x3 - y3 = (x - y)(x2 + xy + y2).

  1. A is true, R is false

  2. A is false, R is true

  3. Both A and R are true

  4. Both A and R are false

Answer

Given,

a322b3a^3 - 2\sqrt{2}b^3

By using identity,

a3 - b3 = (a - b)(a2 + ab + b2)

(a)3(2b)3(a2b)(a2+a(2b)+(2b)2)(a2b)(a2+2ab+2b2)\Rightarrow (a)^3 - (\sqrt{2}b)^3 \\[1em] \Rightarrow (a - \sqrt{2}b)(a^2 + a(\sqrt{2}b) + (\sqrt{2}b)^2) \\[1em] \Rightarrow (a - \sqrt{2}b)(a^2 + \sqrt{2}ab + 2b^2) \\[1em]

Assertion (A) is false.

Given,

x3 - y3 = (x - y)(x2 + xy + y2)

This is a identity.

Reason (R) is true.

A is false, R is true.

Hence, option 2 is correct option.

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