Factorise :
2ab2c - 2a + 3b3c - 3b - 4b2c2 + 4c
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= 2a(b2c - 1) + 3b(b2c - 1) - 4c(b2c - 1)
= (b2c - 1)(2a + 3b - 4c)
Hence,2ab2c - 2a + 3b3c - 3b - 4b2c2 + 4c = (b2c - 1)(2a + 3b - 4c)
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2ab2 - aby + 2cby - cy2
ax + 2bx + 3cx - 3a - 6b - 9c
(2x + y)2 - (2y + x)2 is equal to:
3(x + y) (x - y)
2(x - y) (x + y)
2(y - x) (x + y)
(3x + y) (3x - y)
49 - (x + 5)2 is equal to:
(54 - x) (54 + x)
(2 - x) (12 + x)
48(x + 5)2
48(x - 5)2