Mathematics
5 + x ≤ 2x < x - 2, x ∈ R.
Statement (1) : There is no value of x ∈ R that satisfies the given inequation.
Statement (2) : 5 + x - x ≤ 2x - x < x - 2 - x ⇒ 5 ≤ x < -2
Both the statements are true.
Both the statements are false.
Statement 1 is true, and statement 2 is false.
Statement 1 is false, and statement 2 is true.
Linear Inequations
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Answer
Both the statements are true.
Reason
Given,
5 + x ≤ 2x
⇒ 5 ≤ 2x - x
⇒ 5 ≤ x ………. (1)
And, 2x < x - 2
⇒ 2x - x < -2
⇒ x < -2 ………. (2)
There can be no real number which is greater than or equal to 5 and less than -2 at the same time.
∴ Both the statements are true.
Hence, option 1 is correct.
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Related Questions
Inequation 5 - 2x ≥ x - 10, where x ∈ N (Natural numbers)
Assertion (A): 5 - 2x ≥ x - 10 ⇒ -3x ≥ -15 ⇒ x ≥ 5
∴ Solution set = {5, 6, 7, 8, ……….}
Reason (R): 5 - 2x ≥ x - 10 ⇒ 5 + 10 ≥ 3x ⇒ x ≤ 5
∴ Solution set = {1, 2, 3, 4, 5}
A is true, R is false.
A is false, R is true.
Both A and R are true and R is correct reason for A.
Both A and R are true and R is incorrect reason for A.
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Statement 1 is false, and statement 2 is true.
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