Mathematics

8a3 + 1 in the form of factors is :

  1. (2a + 1)(4a2 - 2a + 1)

  2. (2a - 1)(4a2 - 2a + 1)

  3. (2a + 1)(4a2 + 2a + 1)

  4. (2a - 1)(4a2 + 2a + 1)

Factorisation

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Answer

Given,

   8a3 + 1

= (2a)3 + (1)3

= (2a + 1)[(2a)2 - 2a × 1 + (1)2]

= (2a + 1)(4a2 - 2a + 1)

Hence, Option 1 is the correct option.

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