Science
A hammer of mass 500 g, moving at 50 ms-1, strikes a nail. The nail stops the hammer in a very short time of 0.01 s. What is the force of the nail on the hammer?
Laws of Motion
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Answer
Given,
Mass of the hammer (m) = 500 g
Convert g into kg
1000 g = 1 kg
500 g = = 0.5 kg
Initial velocity of the hammer (u) = 50 ms-1
Terminal velocity of the hammer (v) = 0
Time period (t) = 0.01 s
As per the first equation of motion,
a =
Substituting we get,
a = = -5000 ms-2
We know, Force = mass x acceleration
Substituting we get,
F = 0.5 x 5000 = -2500 N
According to the third law of motion, the nail exerts an equal and opposite force on the hammer and as the force exerted on the nail by the hammer is -2500 N, hence, the force exerted on the hammer by the nail will be 2500 N.
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