Science
The following is the distance-time table of an object in motion:
| Time in seconds | Distance in meters |
|---|---|
| 0 | 0 |
| 1 | 1 |
| 2 | 8 |
| 3 | 27 |
| 4 | 64 |
| 5 | 125 |
| 6 | 216 |
| 7 | 343 |
(a) What conclusion can you draw about the acceleration? Is it constant, increasing, decreasing, or zero?
(b) What do you infer about the forces acting on the object?
Laws of Motion
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Answer
(a)
| Time (t) in s | Distance (s) in m | Velocity (v = s/t) in m/s | Acceleration (a = ∆v/∆t) in m/s |
|---|---|---|---|
| 0 | 0 | 0 | 0 |
| 1 | 1 | 1 | 1 |
| 2 | 8 | 4 | 3 |
| 3 | 27 | 9 | 5 |
| 4 | 64 | 16 | 7 |
| 5 | 125 | 25 | 9 |
| 6 | 216 | 36 | 11 |
| 7 | 343 | 49 | 13 |
We notice from the table above that the acceleration of the object is increasing.
(b) We know Force = mass x acceleration
As mass of the object remains same, the increasing acceleration implies that the force acting on the object is increasing as well.
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