Biology
A homozygous plant having round (R) and yellow (Y) seed is crossed with another homozygous plant having wrinkled (r) and green (y) seeds. Answer the following questions :
(a) Give the genotype of the F1 generation.
(b) Mention the phenotype of the F1 offsprings.
(c) Give the possible combinations of gametes that can be obtained from F1 hybrids.
(d) Give the dihybrid phenotypic ratio and the phenotype of the offsprings of the F2 generation when two plants of F1 generation are crossed.
(e) Name and state the law which explains the dihybrid phenotypic ratio.
Genetics
ICSE
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Answer
(a) Genotype : RrYy
(b) All Round and yellow seeds
(c) RY, Ry, rY, ry
(d) 9:3:3:1
(e) Law of Independent Assortment, which states that the distribution of the alleles of one character into the gametes is independent of the distribution of the alleles of the other character.
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Mendel crossed a homozygous pea plant having round seeds (RR) with a homozygous pea plant having wrinkled seeds (rr). He got different results. On the basis of it, answer the following questions:
(a) Which character of seed is studied in the experiment?
(b) Which of the above two traits is dominant ?
(c) Write the phenotype and genotype of F1 offspring.
(d) Mention and state the Mendel’s law shown in the above cross.
(e) Make a Punnett square for F2 generation when two plants of F1 offspring are crossed with each other.
(f) Write the phenotypic ratio of F2 progeny.
(g) What will be the genotypic ratio of F2 offsprings ?
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