KnowledgeBoat Logo
|

Mathematics

A lot consist of 48 mobile phones of which 42 are good, 3 have only minor defects and 3 have major defects. Varnika will buy a phone if it is good but the trader will only buy a mobile if it has no major defect. One phone is selected at random from the lot. What is the probability that it is

(i) acceptable to Varnika?

(ii) acceptable to the trader?

Probability

10 Likes

Answer

Total phones = 48.

(i) Varnika accepts good phones only, hence no. of favourable outcomes acceptable to Varnika = 42.

P(acceptable to Varnika) = 4248=78.\dfrac{42}{48} = \dfrac{7}{8}.

Hence, the probability that a phone is acceptable to Varnika is 78.\dfrac{7}{8}.

(ii) Trader accepts good phones and one with minor defects only, hence no. of favourable outcomes acceptable to trader = 42 + 3 = 45.

P(acceptable to trader) = 4548=1516.\dfrac{45}{48} = \dfrac{15}{16}.

Hence, the probability that a phone is acceptable to trader is 1516.\dfrac{15}{16}.

Answered By

7 Likes


Related Questions