KnowledgeBoat Logo
|

Mathematics

Assertion (A): A die is thrown once and the probability of getting an even number is 23\dfrac{2}{3}.

Reason (R): The sample space for even number on a die is {2, 4, 6}.

  1. Assertion (A) is true, but Reason (R) is false.

  2. Assertion (A) is false, but Reason (R) is true.

  3. Both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

  4. Both Assertion (A) and Reason (R) are correct, and Reason (R) is incorrect reason for Assertion (A).

Probability

2 Likes

Answer

On the faces of a die, numbers are 1, 2, 3, 4, 5 and 6. Out of which 2, 4 and 6 are even numbers.

So, the sample space for even number on a die = {2, 4, 6}

∴ Reason (R) is true.

Number of favourable outcomes = 3 (for getting even numbers)

The total number of possible outcomes = 6

P(getting a even number) = No. of favourable outcomesNo. of possible outcomes=36=12\dfrac{\text{No. of favourable outcomes}}{\text{No. of possible outcomes}} = \dfrac{3}{6} = \dfrac{1}{2}.

∴ Assertion (A) is false.

∴ Assertion (A) is false, but Reason (R) is true.

Hence, option 2 is the correct option.

Answered By

2 Likes


Related Questions