Mathematics
In a single throw of die, find the probability of getting
(i) a number greater than 5
(ii) an odd prime number
(iii) a number which is multiple of 3 or 4.
Probability
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Answer
When a die is thrown once, the possible outcomes are the numbers 1, 2, 3, 4, 5, 6. So, the sample space of the experiment = {1, 2, 3, 4, 5, 6}. It has six equally likely outcomes.
(i) The event is getting number greater than 5 i.e. {6}
The number of favourable outcomes to the event getting number greater than 5 = 1.
∴ P(getting number greater than 5) = .
Hence, the probability of getting a number greater than 5 is .
(ii) The event is getting an odd prime number i.e. {3, 5}
The number of favourable outcomes to the event an odd prime number = 2.
∴ P(getting an odd prime number) = .
Hence, the probability of getting an odd prime number is .
(iii) The event is getting a number which is a multiple of 3 or 4 i.e. {3, 4, 6}
The number of favourable outcomes to the above event = 3.
∴ P(getting a number which is a multiple of 3 or 4) = .
Hence, the probability of getting a number which is a multiple of 3 or 4 is .
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