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Mathematics

A man invested ₹46875 at 4% per annum compound interest for 3 years. Calculate :

(i) the interest for the first year.

(ii) the amount standing to his credit at the end of the second year.

(iii) the interest for the third year.

Compound Interest

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Answer

(i) Principal for first year = ₹46875.

Interest for the first year = ₹ 46875×4×1100=187500100\dfrac{46875 \times 4 \times 1}{100} = \dfrac{187500}{100} = ₹1875.

Hence, the interest for the first year = ₹1875.

(ii) Amount after one year = ₹46875 + ₹1875 = ₹48750.

Principal for the second year = ₹48750.

Interest for the second year = ₹ 48750×4×1100=195000100\dfrac{48750 \times 4 \times 1}{100} = \dfrac{195000}{100} = ₹1950.

Amount after 2 years = ₹48750 + ₹1950 = ₹50700.

Hence, the amount standing to his credit at the end of the second year is ₹50700.

(iii) Principal for third year = ₹50700.

Interest for the third year = ₹ 50700×4×1100=202800100\dfrac{50700 \times 4 \times 1}{100} = \dfrac{202800}{100} = ₹2028.

Hence, the interest for the third year = ₹2028.

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