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Mathematics

Calculate the compound interest for the second year on ₹8000 invested for 3 years at 10% p.a.

Also find the sum due at the end of third year.

Compound Interest

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Answer

Principal for first year = ₹8000.

Interest for the first year = ₹ 8000×10×1100\dfrac{8000 \times 10 \times 1}{100} = ₹800.

Amount after one year = ₹8000 + ₹800 = ₹8800.

Principal for the second year = ₹8800.

Interest for the second year = ₹ 8800×10×1100\dfrac{8800 \times 10 \times 1}{100} = ₹880.

Amount after 2 years = ₹8800 + ₹880 = ₹9680.

Principal for the third year = ₹9680.

Interest for the third year = ₹ 9680×10×1100\dfrac{9680 \times 10 \times 1}{100} = ₹968.

Amount after 3 years = ₹9680 + ₹968 = ₹10648.

Hence, the compound interest for the second year on ₹8000 invested for 3 years at 10% p.a. is ₹880 and the sum due at the end of third year is ₹10648.

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