Ramesh invested ₹12800 for three years at the rate of 10% per annum compound interest. Find :

(i) the sum due to Ramesh at the end of the first year.

(ii) the interest he earns for the second year.

(iii) the total amount due to him at the end of three years.

(i) Principal for first year = ₹12800.

Interest for the first year = ₹ $\dfrac{12800 \times 10 \times 1}{100} = \dfrac{128000}{100}$ = ₹1280.

Amount after first year = ₹12800 + ₹1280 = ₹14080

Hence, the sum due to Ramesh at the end of first year = ₹14080.

(ii) Principal for the second year = ₹14080.

Interest for the second year = ₹ $\dfrac{14080 \times 10 \times 1}{100} = \dfrac{140800}{100}$ = ₹1408.

Hence, the interest Ramesh earns for second year = ₹1408.

(iii) Amount after 2 years = ₹14080 + ₹1408 = ₹15488.

Interest for the third year = ₹ $\dfrac{15488 \times 10 \times 1}{100} = \dfrac{154880}{100}$ = ₹1548.80

Amount after 3 years = ₹15488 + ₹1548.80 = ₹17036.80

Hence, the total amount due to Ramesh at the end of third year is ₹17036.80