Mathematics
In a ΔABC, AB = 10 cm, AC = 14 cm and BC = 6 cm. If AD is the internal bisector of ∠A, then CD is equal to:
3.5 cm
4.8 cm
7 cm
10.5 cm

Related Questions
In the adjoining figure, ∠ADE = ∠ABC, AE = 8 cm, EB = 7 cm, BC = 9 cm, AD = 10 cm and DC = 2 cm. Then the length of DE is:
6 cm
6.75 cm
7.8 cm
13.5 cm

In ΔABC, it is given that AB = 9 cm, BC = 6 cm and CA = 7.5 cm. Also ΔDEF is given such that EF = 8 cm and ΔDEF ∼ ΔABC. Then the perimeter of ΔDEF is:
22.5 cm
25 cm
27 cm
30 cm
In the given figure, two line segments AC and BD intersect each other at point P such that PA = 6 cm, PB = 3 cm, PC = 2.5 cm, PD = 5 cm, ∠APB = 50° and ∠CDP = 30°. Then ∠PBA = ?
30°
50°
60°
100°

ABCD is a trapezium with AB parallel to DC. Then the triangle similar to ΔAOB is:
ΔACB
ΔADB
ΔCOB
ΔCOD
