In the given figure, AD bisects ∠A. If ∠B = 60°, ∠C = 40°, then arrange AB, BD and DC in ascending order of their lengths.

In the given figure, ∠ABC = 66°, ∠DAC = 38°. CE is perpendicular to AB and AD is perpendicular to BC. Prove that: CP > AP.

In a △PQR, ∠Q = 50°, ∠R = 65° and QR = 4 cm. Then PQ =

1. 6 cm

2. 5 cm

3. 4 cm

4. 3 cm

In the adjoining figure, ∠ABC = 90°, ∠BCA = 50° and BD ⊥ AC. Then ∠ABD =

1. 30°

2. 40°

3. 50°

4. 60°