Mathematics
In a △ABC, AB = AC and ∠B = 50°. Then ∠A =
50°
80°
100°
105°
Triangles
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Answer
In △ABC,
AB = AC
⇒ ∠B = ∠C = 50° (Angles opposite to equal sides in a triangle are equal)
By angle sum property of triangle,
⇒ ∠A + ∠B + ∠C = 180°
⇒ ∠A + 50° + 50° = 180°
⇒ ∠A + 100° = 180°
⇒ ∠A = 180° - 100°
⇒ ∠A = 80°.
Hence, option 2 is the correct option.
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