Mathematics
ABCD is a trapezium with AB parallel to DC. Then the triangle similar to ΔAOB is:
ΔACB
ΔADB
ΔCOB
ΔCOD
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Answer
Given,
Consider ΔAOB and ΔCOD
∠AOB = ∠COD [Vertically opposite angles are equal]
∠OBA = ∠ODC [Alternate angles are equal]
Therefore, by AA rule of similarity ΔAOB ~ ΔCOD.
Hence, option 4 is the correct option.
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