Mathematics
AD is altitude of an isosceles triangle ABC in which AB = AC = 30 cm and BC = 36 cm. A point O is marked on AD in such a way that ∠BOC = 90°. Find the area of quadrilateral ABOC.
Related Questions
Assertion (A): The perimeter of the adjoining figure is (32 + x) cm.
Reason (R): x2 = 132 - 52 = 144 and x = 12 cm.
Perimeter = (32 + 12) cm
A is true, but R is false.
A is false, but R is true.
Both A and R are true, and R is the correct reason for A.
Both A and R are true, and R is the incorrect reason for A.
Assertion (A): If BC = 14 cm, AB = 14 x 4 cm
Reason (R): AB = 4 x 2r = 4 x 14 cm
A is true, but R is false.
A is false, but R is true.
Both A and R are true, and R is the correct reason for A.
Both A and R are true, and R is the incorrect reason for A.
A footpath of uniform width runs all around the outside of a rectangular field 30 m long and 24 m wide. If the path occupies an area of 360 m2, find its width.
A wire when bent in the form of a square encloses an area of 484 m2. Find the largest area enclosed by the same wire when bent to form :
(i) an equilateral triangle.
(ii) a rectangle of breadth 16 m.