Mathematics
In the adjoining figure, ABCD is a parallelogram. P is a point on DC such that ar (ΔAPD) = 25 cm2 and ar (ΔBPC) = 15 cm2. Calculate :
(i) ar (∥ gm ABCD)
(ii) DP : PC
Related Questions
In the adjoining figure, ABCD is a parallelogram. Any line through A cuts DC at a point P and BC produced at Q. Prove that : ar (ΔBPC) = ar (ΔDPQ).
In the adjoining figure, ABCD is a parallelogram. P is a point on BC such that BP : PC = 1 : 2. DP produced meets AB produced at Q. Given ar (ΔCPQ) = 20 cm2. Calculate :
(i) ar (ΔCDP)
(ii) ar (∥ gm ABCD)
In the given figure, AB ∥ DC ∥ EF, AD ∥ BE and DE ∥ AF. Prove that : ar (∥ gm DEFH) = ar (∥ gm ABCD).
In the given figure, squares ABDE and AFGC are drawn on the side AB and hypotenuse AC of right triangle ABC and BH ⟂ FG. Prove that :
(i) ∠EAC = ∠BAF
(ii) ar (sq. ABDE) = ar (rect. ARHF)
