Mathematics
In the adjoining figure, ABCD is a parallelogram. P and Q are any two points on the sides AB and BC respectively. Prove that :
ar (ΔCPD) = ar (ΔAQD).
Related Questions
In the given figure, AD is a median of ΔABC and P is a point on AC such that :
ar (ΔADP) : ar (ΔABD) = 2 : 3.
Find :
(i) AP : PC
(ii) ar (ΔPDC) : ar (ΔABC)
In the given figure, P is a point on side BC of ΔABC such that BP : PC = 1 : 2 and Q is a point on AP such that PQ : QA = 2 : 3. Show that :
ar (ΔAQC) : ar (ΔABC) = 2 : 5.
In the adjoining figure, DE ∥ BC. Prove that :
(i) ar (ΔABE) = ar (ΔACD)
(ii) ar (ΔOBD) = ar (ΔOCE)
In the given figure, ABCD is a parallelogram and P is a point on BC. Prove that :
ar (ΔABP) + ar (ΔDPC) = ar (ΔAPD).
