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Mathematics

Angle AOB is:
60°
90°
45°
none of these

Pythagoras Theorem

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Answer

Since, AO = BO = x

Squaring all the sides we get :

AB² = $(x\sqrt{2})^2 = 2x^2$

OB = x²

OA = x²

In triangle AOB,

⇒ AO² + BO² = x² + x² = 2x² = AB².

Thus, AOB is a right angle triangle with AB as hypotenuse.

Since, AB is hypotenuse, then ∠AOB (angle opposite to hypotenuse) = 90°

Hence, option 2 is the correct option.

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