Ranbeer runs 10 km due North and 24 km due West. The distance between his two position is:

1. 34 km

2. 17 km

3. 26 km

4. none of these

Starting from point A, Ranbeer runs 10 km due north and reached at point B then 24 km due west, ending at point C.

According to Pythagoras Theorem, in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.

⇒ Hypotenuse² = Base² + Height²

In triangle ABC,

⇒ AC² = AB² + BC²

⇒ AC² = 10² + 24²

⇒ AC² = 100 + 576

⇒ AC² = 676

⇒ AC = $\sqrt{676}$

⇒ AC = 26 km.

Hence, option 3 is the correct option.