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Assertion (A): ABCD is a square. E is mid-point of side AB and F is mid-point of side DC. If DA = 16 cm, the area of triangle COF is 32 cm2.

ABCD is a square. E is mid-point of side AB and F is mid-point of side DC. If DA = 16 cm, the area of triangle COF is 32 cm2. Area Theorems, Concise Mathematics Solutions ICSE Class 9.

Reason (R): EF is ⊥ to DC and OF = 12EF=12\dfrac{1}{2} \text{EF} = \dfrac{1}{2} DA = 8 cm.

Area of COF = 12\dfrac{1}{2} x CF x OF

  1. A is true, but R is false.

  2. A is false, but R is true.

  3. Both A and R are true, and R is the correct reason for A.

  4. Both A and R are true, and R is the incorrect reason for A.

Theorems on Area

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Answer

Given, ABCD is a square. DA = 16 cm.

∴ AB = BC = CD = DA = 16 cm

F is mid-point of DC.

CF = 12\dfrac{1}{2} x DC = 12\dfrac{1}{2} x 16 = 8 cm.

If EF is ⊥ to DC, then OF is perpendicular to DC.

Area of ΔCOF = 12\dfrac{1}{2} x base x height

= 12\dfrac{1}{2} x CF x OF

= 12\dfrac{1}{2} x 8 x 8

= 4 x 8

= 32 cm2.

∴ Both A and R are true, and R is the correct reason for A.

Hence, option 3 is the correct option.

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