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Mathematics

Assertion (A): In the adjoining figure, AB is a diameter of the circle. If P is any point on the circle, then AB2 = AP2 + BP2.

Reason (R): Angle in a semicircle is 90°.

In the adjoining figure, AB is a diameter of the circle. If P is any point on the circle, then AB2 = AP2 + BP2.Reason : Angle in a semicircle is 90°. Circles, ML Aggarwal Understanding Mathematics Solutions ICSE Class 10.
  1. Assertion (A) is true, but Reason (R) is false.

  2. Assertion (A) is false, but Reason (R) is true.

  3. Both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

  4. Both Assertion (A) and Reason (R) are correct, and Reason (R) is incorrect reason for Assertion (A).

Circles

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Answer

Given,

AB is the diameter of the circle.

We know that,

Angle in a semi-circle is a right angle.

So, reason (R) is true.

∠APB = 90°

We know that,

Side opposite to 90° is hypotenuse.

Thus, in triangle APB, AB is the hypotenuse.

Using pythagoras theorem in ΔAPB,

⇒ Hypotenuse2 = Base2 + Perpendicular2

⇒ AB2 = BP2 + AP2

So, assertion (A) is true.

Thus, both Assertion (A) and Reason (R) are correct, and Reason (R) is the correct reason for Assertion (A).

Hence, option 3 is the correct option.

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