Mathematics
Assertion (A):
| Class interval | Frequency | Cumulative Frequency |
|---|---|---|
| 0 - 5 | 5 | 5 |
| 5 - 10 | 9 | 14 |
| 10 - 15 | a | 22 |
| 15 - 20 | 6 | 28 |
| 20 - 25 | 10 | b |
⇒ a = 22 and b = 10
Reason (R):
14 + a = 22 ⇒ a = 8
28 + 10 = b ⇒ b = 38
- A is true, R is false.
- A is false, R is true.
- Both A and R are true.
- Both A and R are false.
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Answer
A is false, R is true.
Explanation
The cumulative frequency for (10 - 15) interval is 22.
The previous cumulative frequency is 14, and the frequency for the interval (10 - 15) is a.
14 + a = 22
⇒ a = 22 - 14
⇒ a = 8
The cumulative frequency for (20 - 25) interval is b.
The previous cumulative frequency is 28, and the frequency for this interval is 10.
28 + 10 = b
⇒ b = 38
According to Assertion, a = 22 (≠ 8) and b = 10 (≠ 38).
∴ Assertion (A) is false.
From the above calculation,
a = 8 and b = 38
∴ Reason (R) is true.
Hence, Assertion (A) is false, Reason (R) is true.
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