Mathematics
Assertion (A): In a frequency distribution the class marks are 5, 15 and 25. The corresponding class-intervals are 5 - 15 and 15 - 25. Reason (R): ∵ 15 - 5/2 = 5 and 25 - 15/2 = 5 ∴ Class-intervals are : (5 - 5) - (5 + 5), (15 - 5) - (15 + 5) and (25 - 5) - (25 + 5) 1. A is true, R is false. 2. A is false, R is true. 3. Both A and R are true. 4. Both A and R are false.
Related Questions
Assertion (A): The median of : 25, 16, 26, 32, 31, 19, 28, 35 is 31.
Reason (R): To find median of the given data, the variate: x1, x2 , x3, ……………, xn needs to be arranged in ascending or descending order.
- A is true, R is false.
- A is false, R is true.
- Both A and R are true.
- Both A and R are false.
Assertion (A):
Class interval Frequency Cumulative Frequency 0 - 5 5 5 5 - 10 9 14 10 - 15 a 22 15 - 20 6 28 20 - 25 10 b ⇒ a = 22 and b = 10
Reason (R):
14 + a = 22 ⇒ a = 8
28 + 10 = b ⇒ b = 38- A is true, R is false.
- A is false, R is true.
- Both A and R are true.
- Both A and R are false.
Assertion (A): The median of a certain set of data is 42. If each data in the set is first increased by 7 and then the result is multiplied by 3, the new median is = (42 + 7) x 3 = 147
Reason (R): The resulting median = 42 + 7 x 3 = 42 + 21 = 63
- A is true, R is false.
- A is false, R is true.
- Both A and R are true.
- Both A and R are false.