Mathematics
Assertion (A): In the given figure, square ABCD and △APB are equal in area.

Reason (R): Square ABCD and △APB are on the same base (AB) and between the same parallels (AB//DP).
⇒ Area of △APB =
- A is true, R is false.
- A is false, R is true.
- Both A and R are true.
- Both A and R are false.
Theorems on Area
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Answer
A is false, R is true.
Explanation
Given,
ABCD is a square.
AB is parallel to CD.
△APB shares the base AB with square ABCD.
The height of △APB is equal to the side of the square (h).
Let BC = h (height of square)
Height of triangle = h (height of square)
Area of (Δ ABP) = x base x height
= x AB x h
= x h x h (∴ As all sides of square are equal)
= x h2 …………..(1)
Area of square ABCD = (side)2
= h2…………..(2)
From (1) and (2),
Area of (Δ ABP) = x Area of square ABCD
∴ Assertion (A) is false.
As proved above,
Area of (Δ ABP) = x Area of square ABCD
∴ Reason (R) is true.
Hence, Assertion (A) is false, Reason (R) is true.
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Related Questions
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Reason (R):

∠AOB =
∠OAB = ∠OBA =
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Reason (R): OB = OD =

and OC = OA =
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Similarly, ∠c = ∠d = 45°
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Area of △AOB : area of △ABC = 1 : 4

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==
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Assertion (A): AM and BN are tangents to the same circle at points A and B respectively. Then AN = BM.

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- A is false, R is true.
- Both A and R are true.
- Both A and R are false.