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Mathematics

Assertion (A): PQR is an equilateral triangle. The co-ordinates of point Q are (0, 222\sqrt{2}).

PQR is an equilateral triangle. The co-ordinates of point Q are Co-ordinate Geometry, Concise Mathematics Solutions ICSE Class 9.

Reason (R): In ΔOPQ,

OQ2 = PQ2 - OP2 = 42 - 22 = 12.

  1. A is true, but R is false.

  2. A is false, but R is true.

  3. Both A and R are true, and R is the correct reason for A.

  4. Both A and R are true, and R is the incorrect reason for A.

Coordinate Geometry

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Answer

The coordinates of R(0, 2) and P(0, -2).

Using distance formula,

Distance between two points = (x2x1)2+(y2y1)2\sqrt{(x2 - x1)^2 + (y2 - y1)^2}

PR = (00)2+(22)2=(4)2=16=4\sqrt{(0 - 0)^2 + (-2 - 2)^2} = \sqrt{(-4)^2} = \sqrt{16} = 4 units.

Given equilateral triangle PQR.

∴ PQ = QR = PR = 4 units.

In an equilateral triangle, a perpendicular drawn from one of the vertices to the opposite side bisects the side.

∴ OP = 12\dfrac{1}{2} x PR = ​12\dfrac{1}{2} x 4 = 2 units.

In right angle triangle OPQ,

By pythagoras theorem,

⇒ QP2 = OP2 + OQ2

⇒ OQ2 = QP2 - OP2

⇒ OQ2 = 42 - 22

⇒ OQ2 = 16 - 4

⇒ OQ2 = 12

⇒ OQ = 12\sqrt{12}

⇒ OQ = 232\sqrt{3}

Since, OQ = 232\sqrt{3} units and Q lies on x-axis.

Co-ordinates of Q = (232\sqrt{3}, 0).

∴ A is false, but R is true.

Hence, option 2 is the correct option.

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