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Mathematics

Assertion (A): The radius of a hemisphere increases from r cm to 2r cm. The ratio between the surface area of the original hemisphere and the resulting hemisphere is 1 : 4.

Reason (R): Surface area of the first case = πr2 + 2πr2

Surface area of the second case = π(2r)2 + 2π(2r)2

  1. A is true, but R is false.

  2. A is false, but R is true.

  3. Both A and R are true, and R is the correct reason for A.

  4. Both A and R are true, and R is the incorrect reason for A.

Mensuration

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Answer

Let A1 be the surface area of the original hemisphere.

A1 = πr2 + 2πr2 = 3πr2.

Let A2 be the surface area of the resulting hemisphere.

A2 = π(2r)2 + 2π(2r)2

= 3π(2r)2

= 3π x 4r2

= 12πr2.

Ratio between the surface area of the original hemisphere and the resulting hemisphere is :

Ratio =A1A2=3πr212πr2=312=14.\text{Ratio } = \dfrac{A1}{A2}\\[1em] = \dfrac{3πr^2}{12πr^2}\\[1em] = \dfrac{3}{12}\\[1em] = \dfrac{1}{4}.

∴ Both A and R are true, and R is the correct reason for A.

Hence, option 3 is the correct option.

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