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Mathematics

Assertion (A): A sphere is inscribed in a cylinder the ratio of the volume of the cylinder to the volume of the sphere is 1 : 4.

Reason (R): Required ratio = πr2 x 2r : 43\dfrac{4}{3} πr3

A sphere is inscribed in a cylinder the ratio of the volume of the cylinder to the volume of the sphere is 1 : 4. Solids, Concise Mathematics Solutions ICSE Class 9.
  1. A is true, but R is false.

  2. A is false, but R is true.

  3. Both A and R are true, and R is the correct reason for A.

  4. Both A and R are true, and R is the incorrect reason for A.

Mensuration

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Answer

Let r be the radius of the sphere. 

From figure,

The radius of the cylinder is also r and the height of the cylinder is 2r.

By formula,

Volume of a cylinder (Vcylinder) = πr2h

= πr2(2r)

= 2πr3.

By formula,

Volume of a sphere (Vsphere) = 43\dfrac{4}{3} πr3

Ratio of the volume of the cylinder to the volume of the sphere :

Ratio=VcylinderVsphere=2πr343πr3=243=2×34=64=32=3:2.\text{Ratio} = \dfrac{V{cylinder}}{V{sphere}}\\[1em] = \dfrac{2πr^3}{\dfrac{4}{3} πr^3}\\[1em] = \dfrac{2}{\dfrac{4}{3}}\\[1em] = \dfrac{2 \times 3}{4}\\[1em] = \dfrac{6}{4}\\[1em] = \dfrac{3}{2} \\[1em] = 3 : 2.

∴ A is false, but R is true.

Hence, option 2 is the correct option.

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