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Chemistry

At a particular temperature, a certain quantity of gas occupies a volume of 74 cm3 at a pressure of 760 mm. If the pressure is decreased to 740 mm, what will be the volume of the gas at the same temperature?

Gas Laws

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Answer

V1 = Initial volume of the gas = 74 cm3
P1 = Initial pressure of the gas = 760 mm
P2 = Final pressure of the gas = 740 mm
V2 = Final volume of the gas = ?

By Boyle's Law:

P1V1=P2V2\text{P}1 \text{V}1 = \text{P}2 \text{V}2

Substituting the values :

760×74=740×V2V2=74×760740V2=76 cm3760 \times 74 = 740 \times \text{V}2 \\[0.5em] \text{V}2 = \dfrac{74 \times 760 }{740} \\[0.5em] \text{V}_2 = 76 \text{ cm}^3

∴ Final volume of the gas = 76 cm3

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