Factorise :
ax + 2bx + 3cx - 3a - 6b - 9c
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= x(a + 2b + 3c) - 3(a + 2b + 3c)
= (a + 2b + 3c)(x - 3)
Hence,ax + 2bx + 3cx - 3a - 6b - 9c = (a + 2b + 3c)(x - 3)
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ab(c2 + d2) - a2cd - b2cd
2ab2 - aby + 2cby - cy2
2ab2c - 2a + 3b3c - 3b - 4b2c2 + 4c
(2x + y)2 - (2y + x)2 is equal to:
3(x + y) (x - y)
2(x - y) (x + y)
2(y - x) (x + y)
(3x + y) (3x - y)