A bag contains 14 balls out of which x are white. If 6 more white balls are added to the bag, the probability of drawing a white ball is $\Big(\dfrac{1}{2}\Big)$ . The value of x is:
4
6
8
10

Question

A bag contains 14 balls out of which x are white. If 6 more white balls are added to the bag, the probability of drawing a white ball is . The value of x is: 1. 4 2. 6 3. 8 4. 10

KnowledgeBoat · Accepted Answer

Given,

The bag contains 14 balls.

Number of white balls = x

When 6 more white balls are added:

New number of white balls = x + 6

Total number of balls = 14 + 6 = 20

The probability of drawing a white ball now is $\dfrac{1}{2}$ .

∴ $P(\text{White ball}) = \dfrac{\text{Number of white balls}}{\text{Total number of balls}} = \dfrac{1}{2} = \dfrac{x + 6}{20}$

2(x + 6) = 20

x + 6 = $\dfrac{20}{2}$

x + 6 = 10

x = 10 - 6

x = 4

Hence, option 1 is the correct option.

Mathematics

A bag contains 14 balls out of which x are white. If 6 more white balls are added to the bag, the probability of drawing a white ball is $\Big(\dfrac{1}{2}\Big)$ . The value of x is:
4
6
8
10

Probability

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