The king and queen of diamonds are removed from a pack of well-shuffled cards. One card is selected at random from the remaining cards. The probability of getting the king of clubs is:
$\Big(\dfrac{1}{4}\Big)$
$\Big(\dfrac{3}{4}\Big)$
$\Big(\dfrac{1}{50}\Big)$
$\Big(\dfrac{3}{52}\Big)$

Question

The king and queen of diamonds are removed from a pack of well-shuffled cards. One card is selected at random from the remaining cards. The probability of getting the king of clubs is: 1. 2. 3. 4.

KnowledgeBoat · Accepted Answer

A standard deck of cards contains 52 cards.

In this case, 2 cards (the King of Diamonds and the Queen of Diamonds) are removed from the deck.

Total number of outcomes = 50

Let E be the event of getting the card king of clubs,

The number of favorable outcomes to the event E = 1

$\therefore P(E) = \dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \dfrac{1}{50}$

Hence, option 3 is the correct option.

Mathematics

The king and queen of diamonds are removed from a pack of well-shuffled cards. One card is selected at random from the remaining cards. The probability of getting the king of clubs is:
$\Big(\dfrac{1}{4}\Big)$
$\Big(\dfrac{3}{4}\Big)$
$\Big(\dfrac{1}{50}\Big)$
$\Big(\dfrac{3}{52}\Big)$

Probability

Answer

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Mathematics

Probability

Answer

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