If cos A = sin B, show that A + B = 90°.
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Given:
cos A = sin B
⇒ cos A = cos (90° - B)
So, A = 90° - B
⇒ A + B = 90°
Hence, If cos A = sin B, then A + B = 90°.
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In each case, given below, find the value of angle A, where 0° ≤ A ≤ 90°.
(i) sin (90° - 3A) . cosec 42° = 1
(ii) cos (90° - A) . sec 77° = 1
Show that :
tan 56° tan 28° tan 34° tan 62° = 1.
If cos 47° sec (90° - θ) = 1; find the angle θ such that 0° ≤ θ ≤ 90°.