Mathematics
Draw a line MN = 5.8 cm. Locate a point A which is 4.5 cm from M and 5 cm from N. Through A draw a line parallel to line MN.
Answer
Steps:
Draw a line MN = 5.8 cm.
With M as center and radius equal to 4.5 cm, draw an arc.
With N as center and radius equal to 5 cm, draw an arc which cuts previous arc at point A.
Take any point P in line MN and join it with the given point A.
At point A, construct ∠NPA = ∠PAB.
Produce AB upto any point C.

Hence, BAC is the required parallel line.
Related Questions
Draw a line segment AB = 5.5 cm. Mark a point P, such that PA = 6 cm and PB = 4.8 cm. From the point P, draw a perpendicular to AB.
Draw a line AB = 6 cm. Mark a point P any where outside the line AB. Through the point P, construct a line parallel to AB.
Draw a straight line AB = 6.5 cm. Draw another line which is parallel to AB at a distance of 2.8 cm from it.
Construct an angle PQR = 60°. Draw a line parallel to PQ at a distance of 3 cm from it and another line parallel to QR at a distance of 3.5 cm from it. Mark the point of intersection of these parallel lines as A.