Mathematics
Draw a straight line AB = 6.5 cm. Draw another line which is parallel to AB at a distance of 2.8 cm from it.
Quadrilaterals Constructions
12 Likes
Answer
Steps:
Draw a line AB = 6.5cm.
At any point P in line AB, draw PQ perpendicular to AB.
With P as centre and radius equal to 2.8 cm, draw an arc which cuts PQ at point R.
At point R, draw RD perpendicular to PQ.
Produce DR upto any point C.
Hence, CD is the required parallel line.
Answered By
11 Likes
Related Questions
Draw a line AB = 6 cm. Mark a point P any where outside the line AB. Through the point P, construct a line parallel to AB.
Draw a line MN = 5.8 cm. Locate a point A which is 4.5 cm from M and 5 cm from N. Through A draw a line parallel to line MN.
Construct an angle PQR = 60°. Draw a line parallel to PQ at a distance of 3 cm from it and another line parallel to QR at a distance of 3.5 cm from it. Mark the point of intersection of these parallel lines as A.
Draw an angle ABC = 60°. Draw the bisector of it. Also draw a line parallel to BC at a distance of 2.5 cm from it.
Let this parallel line meet AB at point P and angle bisectors at point Q. Measure the lengths of BP and PQ. Is BP = PQ ?