Draw an ogive for the following distribution :

Income in ₹	No. of employees
120 - 140	30
140 - 160	72
160 - 180	90
180 - 200	80
200 - 220	70
220 - 240	28

Use the ogive drawn to determine :

(i) the median income,

(ii) the number of employees whose income exceeds ₹ 190.

Cumulative frequency distribution table :

(i) Here, n = 370, which is even,

Median = $\dfrac{n}{2} = \dfrac{370}{2}$ = 185.

Steps of construction :

1. Take 2 cm = ₹ 20 on x-axis.

2. Take 1 cm = 50 employees on y-axis.

3. A kink is shown near x-axis as it starts from 120. Plot the point (120, 0) as ogive starts on x-axis representing lower limit of first class.

4. Plot the points (140, 30), (160, 102), (180, 192), (200, 272), (220, 342) and (240, 370).

5. Join the points by a free-hand curve.

6. Draw a line parallel to x-axis from point H (no. of employees) = 185, touching the graph at point I. From point I draw a line parallel to y-axis touching x-axis at point J.

From graph, J = 179

Hence, median wage = ₹ 179.

(ii) Steps :

1. Draw a line parallel to y-axis from point K (income) = ₹ 190, touching the graph at point L. From point L draw a line parallel to x-axis touching y-axis at point M.

From graph, M = 232

It means that,

232 employees have income less than or equal to ₹ 190.

∴ No. of employees having income more than ₹ 190 = 370 - 232 = 138.

Hence, no. of employees having income more than ₹ 190 = 138.