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Mathematics

Evaluate :

3 sin 72° cos 18°\text{3}\dfrac{\text{ sin 72°}}{\text{ cos 18°}} - sec 32°cosec 58°\dfrac{\text{sec 32°}}{\text{cosec 58°}}

Trigonometric Identities

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Answer

3 sin 72° cos 18°sec 32°cosec 58°=3 sin (90° - 18°) cos 18°sec (90° - 58°)cosec 58°=3 cos 18° cos 18°cosec 58°cosec 58°=3cos18°cos18°cosec58°cosec58°=31=2\text{3}\dfrac{\text{ sin 72°}}{\text{ cos 18°}} - \dfrac{\text{sec 32°}}{\text{cosec 58°}}\\[1em] = \text{3}\dfrac{\text{ sin (90° - 18°)}}{\text{ cos 18°}} - \dfrac{\text{sec (90° - 58°)}}{\text{cosec 58°}}\\[1em] = \text{3}\dfrac{\text{ cos 18°}}{\text{ cos 18°}} - \dfrac{\text{cosec 58°}}{\text{cosec 58°}}\\[1em] = \text{3}\dfrac{\cancel{ cos 18°}}{\cancel{ cos 18°}} - \dfrac{\cancel{cosec 58°}}{\cancel{cosec 58°}}\\[1em] = 3 - 1\\[1em] = 2

Hence, 3 sin 72° cos 18°sec 32°cosec 58°=2\text{3}\dfrac{\text{ sin 72°}}{\text{ cos 18°}} - \dfrac{\text{sec 32°}}{\text{cosec 58°}} = 2.

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