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Mathematics

Evaluate :

sin 80°cos 10°\dfrac{\text{sin 80°}}{\text{cos 10°}} + sin 59° sec 31°

Trigonometric Identities

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Answer

sin 80°cos 10°+sin 59° sec 31°=sin (90° - 10°)cos 10°+sin (90° - 31°) sec 31°=cos 10°cos 10°+cos 31° sec 31°=cos10°cos10°+cos 31°1cos 31°=1+cos31°1cos31°=1+1=2\dfrac{\text{sin 80°}}{\text{cos 10°}} + \text{sin 59° sec 31°}\\[1em] = \dfrac{\text{sin (90° - 10°)}}{\text{cos 10°}} + \text{sin (90° - 31°) sec 31°}\\[1em] = \dfrac{\text{cos 10°}}{\text{cos 10°}} + \text{cos 31° sec 31°}\\[1em] = \dfrac{\cancel{cos 10°}}{\cancel{cos 10°}} + \text{cos 31°}\dfrac{1}{\text{cos 31°}}\\[1em] = 1 + \cancel{cos 31°}\dfrac{1}{\cancel{cos 31°}}\\[1em] = 1 + 1\\[1em] = 2

Hence, sin 80°cos 10°+sin 59° sec 31°=2\dfrac{\text{sin 80°}}{\text{cos 10°}} + \text{sin 59° sec 31°} = 2.

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