Expand: (a + b - c)^2

(a \+ b \- c) 2 Using the formula, [∵ (x \+ y \- z) 2 = x 2 \+ y 2 \+ z 2 \+ 2xy \- 2yz \- 2xz] = a 2 \+ b 2 \+ c 2 \+ 2ab \- 2bc \- 2ca Hence, (a \+ b \- c) 2 = a 2 \+ b 2 \+ c 2 \+ 2ab \- 2bc \- 2ca

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(a + b - c)²

Using the formula,

[∵ (x + y - z)² = x² + y² + z² + 2xy - 2yz - 2xz]

= a² + b² + c² + 2ab - 2bc - 2ca

Hence, (a + b - c)² = a² + b² + c² + 2ab - 2bc - 2ca

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(a + b - c)²

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