Factorise:
1 - 2(a + 2b) - 3(a + 2b)2
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Given,
⇒ 1 - 2(a + 2b) - 3(a + 2b)2
⇒ 1 - 3(a + 2b) + (a + 2b) - 3(a + 2b)2
⇒ 1[1 - 3(a + 2b)] + (a + 2b)[1 - 3(a + 2b)]
⇒ (1 + a + 2b)[1 - 3(a + 2b)]
⇒ (1 + a + 2b)(1 - 3a - 6b).
Hence, 1 - 2(a + 2b) - 3(a + 2b)2 = (1 + a + 2b)(1 - 3a - 6b).
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