Factorise :
1 - 2a - 3a2
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Given,
= -(3a2 + 2a - 1)
= -[3a2 + 3a - a - 1]
= -[3a(a + 1) - 1(a + 1)]
= -(3a - 1)(a + 1)
= (1 - 3a)(a + 1).
Hence, 1 - 2a - 3a2 = (1 - 3a)(a + 1).
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x(x - 1) - 20 in the form of factors is :
(x - 5)(x + 4)
(x - 5)(x - 4)
(x + 5)(x - 4)
(x + 5)(x + 4)
5 - x(6 - x) in the form of factors is :
(1 - x)(5 + x)
(1 + x)(5 + x)
(1 - x)(5 - x)
(1 + x)(5 - x)
24a3 + 37a2 - 5a
3 - a(4 + 7a)