Factorise :
a6 + 27b3
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Given,
= (a2)3 + (3b)3
= (a2 + 3b)[(a2)2 - a2 × 3b + (3b)2]
= (a2 + 3b)(a4 - 3a2b + 9b2).
Hence, a6 + 27b3 = (a2 + 3b)(a4 - 3a2b + 9b2).
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