Factorise the following:
2(x - 2y)2 - 50y2
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= 2[(x - 2y)2 - 25y2]
= 2[(x - 2y)2 - (5y)2].
Using identity,
a2 - b2 = (a + b)(a - b).
2[(x - 2y)2 - (5y)2]
= 2(x - 2y + 5y)(x - 2y - 5y) = 2(x + 3y)(x - 7y).
Hence, 2(x - 2y)2 - 50y2 = 2(x + 3y)(x - 7y).
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