Factorise the following: πa 5 - π 3 ab 2

πa 5 - π 3 ab 2 = πa(a 4 - π 2 b 2 ) = πa[(a 2 ) 2 - (πb) 2 ]. Using identity, a 2 - b 2 = (a - b)(a + b). πa[(a 2 ) 2 - (πb) 2 ] = πa(a 2 - πb)(a 2 + πb). Hence, πa 5 - π 3 ab 2 = πa(a 2 - πb)(a 2 + πb).

Mathematics

Factorise the following:
πa⁵ - π³ab²

Factorisation

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Answer

πa⁵ - π³ab²

= πa(a⁴ - π²b²)

= πa[(a²)² - (πb)²].

Using identity,

a² - b² = (a - b)(a + b).

πa[(a²)² - (πb)²] = πa(a² - πb)(a² + πb).

Hence, πa⁵ - π³ab² = πa(a² - πb)(a² + πb).

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Mathematics

Factorise the following:
πa⁵ - π³ab²

Factorisation

Answer

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Mathematics

Factorise the following:πa5 - π3ab2

Factorisation

Answer

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