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Mathematics

If A =[2031] and B =[0123]\text{If A }= \begin{bmatrix}[r] 2 & 0 \ -3 & 1 \end{bmatrix} \text{ and B }= \begin{bmatrix}[r] 0 & 1 \ -2 & 3 \end{bmatrix}, find 2A - 3B.

Matrices

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Answer

2A - 3B =2[2031]3[0123]=[4062][0369]=[4+0036(6)29]=[4307]\text{2A - 3B }= 2\begin{bmatrix}[r] 2 & 0 \ -3 & 1 \end{bmatrix} - 3\begin{bmatrix}[r] 0 & 1 \ -2 & 3 \end{bmatrix} \\[1em] = \begin{bmatrix}[r] 4 & 0 \ -6 & 2 \end{bmatrix} - \begin{bmatrix}[r] 0 & 3 \ -6 & 9 \end{bmatrix} \\[1em] = \begin{bmatrix}[r] 4 + 0 & 0 - 3 \ -6 - (-6) & 2 - 9 \end{bmatrix} \\[1em] = \begin{bmatrix}[r] 4 & -3 \ 0 & -7 \end{bmatrix} \\[1em]

Hence, the matrix 2A - 3B = [4307].\begin{bmatrix}[r] 4 & -3 \ 0 & -7 \end{bmatrix}.

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