Find the area and the perimeter of a square with diagonal 24 cm. [Take = 1.41].

Diagonal of the square = 24 cm Let `a` be the side of square. By using the Pythagoras theorem, AB 2 \+ BC 2 = AC 2 ⇒ a 2 \+ a 2 = (24) 2 ⇒ 2a 2 = 576 ⇒ a 2 = ⇒ a 2 = 288 ⇒ a = ⇒ a = 12 ⇒ a = 12 x 1.41 = 16.92 cm Area of the square = side 2 = () 2 cm 2 = 288 cm 2 Perimeter of the square = 4 x side = 4 x 16.92 cm = 67.68 cm Hence, the area of the square is 288 cm 2 and the perimeter is 67.68 cm.

Using the information in the following figure, find the area of the trapezium.

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Mathematics

Find the area and the perimeter of a square with diagonal 24 cm. [Take = 1.41].

Mensuration

Related Questions

Using the information in the following figure, find the area of the trapezium.

Sum of the areas of two squares is 400 cm². If the difference of their perimeters is 16 cm, find the sides of the two squares.

A steel wire, when bent in the form of a square, encloses an area of 121 cm². The same wire is bent in the form of a circle. Find area of the circle.

The perimeter of a semicircular plate is 108 cm, find its area.

Mathematics

Find the area and the perimeter of a square with diagonal 24 cm. [Take = 1.41].

Mensuration

Related Questions

Using the information in the following figure, find the area of the trapezium.

Sum of the areas of two squares is 400 cm2. If the difference of their perimeters is 16 cm, find the sides of the two squares.

A steel wire, when bent in the form of a square, encloses an area of 121 cm2. The same wire is bent in the form of a circle. Find area of the circle.

The perimeter of a semicircular plate is 108 cm, find its area.

Sum of the areas of two squares is 400 cm². If the difference of their perimeters is 16 cm, find the sides of the two squares.

A steel wire, when bent in the form of a square, encloses an area of 121 cm². The same wire is bent in the form of a circle. Find area of the circle.