Find the area and the perimeter of a square with diagonal 24 cm. [Take = 1.41].

Question

KnowledgeBoat · Accepted Answer

Diagonal of the square = 24 cm Let `a` be the side of square. By using the Pythagoras theorem, AB² \+ BC² = AC² ⇒ a² \+ a² = (24)² ⇒ 2a² = 576 ⇒ a² = ⇒ a² = 288 ⇒ a = ⇒ a = 12 ⇒ a = 12 x 1.41 = 16.92 cm Area of the square = side² = ()² cm² = 288 cm² Perimeter of the square = 4 x side = 4 x 16.92 cm = 67.68 cm Hence, the area of the square is 288 cm² and the perimeter is 67.68 cm.

Mathematics

Find the area and the perimeter of a square with diagonal 24 cm. [Take = 1.41].

Mensuration

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Mathematics

Find the area and the perimeter of a square with diagonal 24 cm. [Take = 1.41].

Mensuration

Related Questions

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